f(4/5) = 2(4/5)^3 - 5(4/5)^2 + 3(4/5) - 1
Question
f(4/5) = 2(4/5)^3 - 5(4/5)^2 + 3(4/5) - 1
Solution
To evaluate the expression f(4/5), we will substitute 4/5 into the given equation:
f(4/5) = 2(4/5)^3 - 5(4/5)^2 + 3(4/5) - 1
Step 1: Simplify the exponents. (4/5)^3 = (4/5) * (4/5) * (4/5) = 64/125 (4/5)^2 = (4/5) * (4/5) = 16/25
Step 2: Substitute the simplified values into the equation. f(4/5) = 2(64/125) - 5(16/25) + 3(4/5) - 1
Step 3: Simplify the multiplications. 2(64/125) = 128/125 5(16/25) = 80/25 3(4/5) = 12/5
Step 4: Substitute the simplified values back into the equation. f(4/5) = 128/125 - 80/25 + 12/5 - 1
Step 5: Simplify the fractions. 128/125 = 1.024 80/25 = 3.2 12/5 = 2.4
Step 6: Substitute the simplified values back into the equation. f(4/5) = 1.024 - 3.2 + 2.4 - 1
Step 7: Perform the additions and subtractions. f(4/5) = -0.752
Therefore, f(4/5) is equal to -0.752.
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