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Instructions: Solve each system by substitution. Make sure to check your answer BEFORE submitting. State your answer as an ordered pair. DO NOT include spaces in your answer.System 1−2x−3y=−2−2𝑥−3𝑦=−2 y=2x+14𝑦=2𝑥+14(( ,, ))System 2−3x−3y=9−3𝑥−3𝑦=9 y=4𝑦=4(( ,, )

Question

Instructions: Solve each system by substitution. Make sure to check your answer BEFORE submitting. State your answer as an ordered pair. DO NOT include spaces in your answer.System 1−2x−3y=−2−2𝑥−3𝑦=−2 y=2x+14𝑦=2𝑥+14(( ,, ))System 2−3x−3y=9−3𝑥−3𝑦=9 y=4𝑦=4(( ,, )

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Solution

System 1:

Given equations are: -2x - 3y = -2 y = 2x + 14

Step 1: Substitute y from the second equation into the first equation: -2x - 3(2x + 14) = -2 -2x - 6x - 42 = -2 -8x = 40 x = -5

Step 2: Substitute x = -5 into the second equation to find y: y = 2(-5) + 14 y = -10 + 14 y = 4

So, the solution to the system is (-5,4).

System 2:

Given equations are: -3x - 3y = 9 y = 4

Step 1: Substitute y = 4 into the first equation: -3x - 3(4) = 9 -3x - 12 = 9 -3x = 21 x = -7

So, the solution to the system is (-7,4).

This problem has been solved

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