An Artisan has 63kg metal of density 7000kg/m^2. He intends to use to make a rectangular pipe of external dimension12cm by15cm and internal dimension10cm by12cm. Calculate the length of the pipe in meters

Sure, let's solve this step by step:

1. First, we need to find the volume of the metal. We know that density = mass/volume. So, rearranging, we get volume = mass/density. Substituting the given values, we get volume = 63kg / 7000kg/m^3 = 0.009 m^3.

2. Next, we need to find the volume of the rectangular pipe. The volume of a rectangular pipe is given by the difference between the volume of the outer rectangle and the volume of the inner rectangle.

3. The volume of a rectangle is given by length x width x height. For the outer rectangle, the length is what we're trying to find, and the width and height are 0.12m and 0.15m respectively. So, the volume of the outer rectangle is (length x 0.12m x 0.15m).

4. Similarly, for the inner rectangle, the length is what we're trying to find, and the width and height are 0.10m and 0.12m respectively. So, the volume of the inner rectangle is (length x 0.10m x 0.12m).

5. Therefore, the volume of the pipe is (length x 0.12m x 0.15m) - (length x 0.10m x 0.12m). Simplifying, we get length = (0.009 m^3) / ((0.12m x 0.15m) - (0.10m x 0.12m)).

6. Solving the above equation will give us the length of the pipe in meters.