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Given x(n) = (-1,2,1,1,-1,1). Plot x(n-1) Impulse functions?

Question

Given x(n) = (-1,2,1,1,-1,1). Plot x(n-1) Impulse functions?

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Solution

Sure, here are the steps to plot x(n-1) for the given x(n) = (-1,2,1,1,-1,1):

  1. Understand the sequence: The given sequence x(n) = (-1,2,1,1,-1,1) is a discrete sequence where n is the index of each element in the sequence.

  2. Shift the sequence: The sequence x(n-1) is a shifted version of x(n). Specifically, it is shifted one unit to the right. This means that each element in x(n) is moved one place to the right to form x(n-1).

  3. Create the new sequence: The new sequence x(n-1) will be (0,-1,2,1,1,-1). The first element is 0 because we have shifted all elements of x(n) one place to the right.

  4. Plot the sequence: Now, you can plot the sequence on a graph. On the x-axis, you have the index n and on the y-axis, you have the value of the sequence at that index.

Please note that this is a theoretical explanation. The actual plotting would depend on the software or method you are using to plot.

As for impulse functions, they are a type of signal used in signal processing and control systems, represented by a spike at a certain value of time (for continuous-time signals) or index (for discrete-time signals). They are not directly related to the task of plotting the sequence x(n-1).

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