The sum of five consecutive odd numbers is equal to 245.what is the difference between twice the largest odd number and the smallest odd number?Options6571615164
Question
The sum of five consecutive odd numbers is equal to 245.what is the difference between twice the largest odd number and the smallest odd number?Options6571615164
Solution
Let's solve this step by step:
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We know that the sum of five consecutive odd numbers is 245. So, we can write this as: n + (n+2) + (n+4) + (n+6) + (n+8) = 245, where n is the smallest odd number.
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Simplifying the equation, we get: 5n + 20 = 245.
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Solving for n, we get: n = (245 - 20) / 5 = 45. So, the smallest odd number is 45.
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The largest odd number in the series would be n + 8 = 45 + 8 = 53.
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The difference between twice the largest odd number and the smallest odd number is: 2*53 - 45 = 106 - 45 = 61.
So, the answer is 61.
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