e) When an aluminum object is immersed in the water, it displaces 5 kg of water. How much is the buoyant force acting on aluminum object in Newton's?[Take g=10ms-²
Question
e) When an aluminum object is immersed in the water, it displaces 5 kg of water. How much is the buoyant force acting on aluminum object in Newton's?[Take g=10ms-²
Solution
The buoyant force acting on an object immersed in a fluid is given by the formula:
Buoyant Force = Weight of the fluid displaced by the object
In this case, the aluminum object displaces 5 kg of water. The weight of this water can be calculated using the formula:
Weight = mass x gravity
So, the weight of the water displaced is 5 kg x 10 m/s² = 50 N.
Therefore, the buoyant force acting on the aluminum object is 50 Newtons.
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