An object moves round a circle of radius 3 m with a constant speed of 6 ms^-1. Its angular velocity and acceleration respectively are *1 point12 rads^-1 and 2 ms^-28 rads^-1 and 2 ms^-26 rads^-1 and 1 ms^-22 rads^-1 and 12 m
Question
An object moves round a circle of radius 3 m with a constant speed of 6 ms^-1. Its angular velocity and acceleration respectively are *1 point12 rads^-1 and 2 ms^-28 rads^-1 and 2 ms^-26 rads^-1 and 1 ms^-22 rads^-1 and 12 m
Solution
The angular velocity (ω) of an object moving in a circle can be calculated using the formula ω = v/r, where v is the speed of the object and r is the radius of the circle.
In this case, the speed (v) is 6 ms^-1 and the radius (r) is 3 m.
So, ω = 6 ms^-1 / 3 m = 2 rads^-1.
The centripetal acceleration (a) of an object moving in a circle can be calculated using the formula a = v^2/r.
So, a = (6 ms^-1)^2 / 3 m = 12 ms^-2.
Therefore, the angular velocity is 2 rads^-1 and the acceleration is 12 ms^-2.
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