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Student_IDFirst_NameLast_NameDOBEmailMajorAllowance1JohnDoe2001-01-15john.doe@example.comComputer [email protected] Administration40003AliceJohnson2001-11-25alice.johnson@example.comElectrical [email protected] Engineering35405CarolBrown1988-07-12carol.brown@example.comBusiness Administration60006AyeyiDjan1999-04-02ayeyi.djan@ashesi.edu.ghComputer Science8000 Student_IDScore180272310425590660 Flag question: Question 3Question 35 ptsDr Stephane Nwolley wants to identify the students with a score greater than the average. Write a MySQL statement to identify these students. Display the student names (Join first name and last name and call it full_name), the score of the student, and their major.

Question

Student_IDFirst_NameLast_NameDOBEmailMajorAllowance1JohnDoe2001-01-15john.doe@example.comComputer [email protected] Administration40003AliceJohnson2001-11-25alice.johnson@example.comElectrical [email protected] Engineering35405CarolBrown1988-07-12carol.brown@example.comBusiness Administration60006AyeyiDjan1999-04-02ayeyi.djan@ashesi.edu.ghComputer Science8000 Student_IDScore180272310425590660 Flag question: Question 3Question 35 ptsDr Stephane Nwolley wants to identify the students with a score greater than the average. Write a MySQL statement to identify these students. Display the student names (Join first name and last name and call it full_name), the score of the student, and their major.

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Solution

Sure, here is the MySQL statement that you can use to identify the students with a score greater than the average. This statement will display the student names (joined first name and last name as full_name), the score of the student, and their major.

SELECT CONCAT(First_Name, ' ', Last_Name) AS full_name, Score, Major
FROM Students
JOIN Scores ON Students.Student_ID = Scores.Student_ID
WHERE Score > (SELECT AVG(Score) FROM Scores);

Here's how this works:

  • The CONCAT(First_Name, ' ', Last_Name) AS full_name part combines the first and last names into a single column called full_name.
  • The FROM Students JOIN Scores ON Students.Student_ID = Scores.Student_ID part joins the Students and Scores tables together based on the Student_ID.
  • The WHERE Score > (SELECT AVG(Score) FROM Scores) part filters out the students whose score is greater than the average score. The average score is calculated with the AVG(Score) function.

This problem has been solved

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