Ratio of thermal energy released in two resistor R and 3R connected in parallel in an electric circuit is :
Question
Ratio of thermal energy released in two resistor R and 3R connected in parallel in an electric circuit is :
Solution
The ratio of thermal energy released in two resistors R and 3R connected in parallel in an electric circuit can be found using the formula for power dissipated in a resistor, which is P = V^2/R, where V is the voltage across the resistor and R is the resistance.
Step 1: Since the resistors are connected in parallel, the voltage across each resistor is the same. Let's denote this common voltage as V.
Step 2: The power dissipated in resistor R is P1 = V^2/R.
Step 3: The power dissipated in resistor 3R is P2 = V^2/(3R).
Step 4: The ratio of the thermal energy released in the two resistors is P1/P2 = (V^2/R) / (V^2/(3R)) = 3.
So, the ratio of thermal energy released in the two resistors R and 3R connected in parallel is 3:1.
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