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6. Baskets of almonds and pecans are bought and sold in a well-functioning market that is in equilibrium. One basket contains 20 almonds and 20 pecans while the second basket contains 10 almonds and 40 pecans. Both baskets are priced at $15. To preclude arbitrage, what is the price of a basket that contains 24 almonds and 16 pecans?  a.$20  b.$18  c.$16  d. It would not have a unique price  e. None of the above

Question

  1. Baskets of almonds and pecans are bought and sold in a well-functioning market that is in equilibrium. One basket contains 20 almonds and 20 pecans while the second basket contains 10 almonds and 40 pecans. Both baskets are priced at 15.Toprecludearbitrage,whatisthepriceofabasketthatcontains24almondsand16pecans?a.15. To preclude arbitrage, what is the price of a basket that contains 24 almonds and 16 pecans?  a.20  b.18c.18  c.16  d. It would not have a unique price  e. None of the above
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Solution

To solve this problem, we first need to determine the price of a single almond and a single pecan.

From the first basket, we know that 20 almonds and 20 pecans cost 15.Therefore,thepriceofonealmondandonepecantogetheris15. Therefore, the price of one almond and one pecan together is 15/20 = $0.75.

From the second basket, we know that 10 almonds and 40 pecans cost 15.Therefore,thepriceofonealmondandfourpecanstogetheris15. Therefore, the price of one almond and four pecans together is 15/10 = $1.50.

From these two pieces of information, we can set up a system of equations to solve for the price of a single almond (A) and a single pecan (P):

1A + 1P = 0.751A+4P=0.75 1A + 4P = 1.50

Solving this system of equations, we find that A = 0.50andP=0.50 and P = 0.25.

Therefore, a basket that contains 24 almonds and 16 pecans would cost 24A + 16P = 24(0.50)+16(0.50) + 16(0.25) = 12+12 + 4 = $16.

So, the answer is c. $16.

This problem has been solved

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