In a diode, the change in voltage being applied across it is 2V. The change in minority carriers outside the depletion region is 1.2×10^-8. Find diffusion capacitance.(1 Point)6 pF6 μF1.2 nF6nF
Question
In a diode, the change in voltage being applied across it is 2V. The change in minority carriers outside the depletion region is 1.2×10^-8. Find diffusion capacitance.(1 Point)6 pF6 μF1.2 nF6nF
Solution
The diffusion capacitance (Cd) of a diode can be calculated using the formula:
Cd = ΔQ/ΔV
Where: ΔQ is the change in charge (minority carriers) and ΔV is the change in voltage.
Given: ΔQ = 1.2×10^-8 C (Coulombs) and ΔV = 2 V (Volts)
Substituting these values into the formula, we get:
Cd = 1.2×10^-8 C / 2 V = 6×10^-9 F
Therefore, the diffusion capacitance of the diode is 6 nF (nanoFarads).
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