To solve for x in the equation log4(x) = -3, you need to convert the logarithmic equation into an exponential equation.

The base of the logarithm becomes the base of the power, the right hand side of the equation becomes the exponent, and x is the result.

So, the equation log4(x) = -3 becomes 4^-3 = x.

4^-3 is 1/4^3 = 1/64.

So, x = 1/64.

Question

To solve for x in the equation log4(x) = -3, you need to convert the logarithmic equation into an exponential equation.

The base of the logarithm becomes the base of the power, the right hand side of the equation becomes the exponent, and x is the result.

So, the equation log4(x) = -3 becomes 4^-3 = x.

4^-3 is 1/4^3 = 1/64.

So, x = 1/64.

Knowee AI · Accepted Answer

To solve for x in the equation log4(x) = -3, you need to convert the logarithmic equation into an exponential equation.

The base of the logarithm becomes the base of the power, the right hand side of the equation becomes the exponent, and x is the result.

So, the equation log4(x) = -3 becomes 4^-3 = x.

4^-3 is 1/4^3 = 1/64.

So, x = 1/64.

When 𝑙𝑜𝑔4𝑥=–3,log 4 x=–3, what is 𝑥x ?