xplain why your expression for the slope of the tangent line in (ii) does not work when x = ±3,and write down equations of those tangent lines.

I'm sorry, but you didn't provide an expression for the slope of the tangent line. However, I can explain in general terms why an expression might not work when x = ±3.

The slope of the tangent line to a function at a given point is given by the derivative of the function at that point. If the derivative is undefined at x = ±3, then the expression for the slope of the tangent line will not work at these points.

This could happen for a number of reasons. For example, if the function has a discontinuity at x = ±3, or if the derivative of the function has a discontinuity at these points, then the expression for the slope of the tangent line will not work.

To write down the equations of the tangent lines at these points, you would need to know the value of the function at these points (the y-coordinate), and the slope of the tangent line at these points. The equation of a line is given by y = mx + b, where m is the slope and b is the y-intercept. If you know the slope of the tangent line and the y-coordinate of the point of tangency, you can substitute these values into the equation to find the y-intercept, and thus the equation of the tangent line.