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Camilla separated prizes for games at the carnival. She had 72 Choco Bars and 90 Peanut Blitzes. She put the most candy bars possible in each bag without mixing the two types. Each bag needed an equal amount of candy. How many candy bars did she put in each bag?

Question

Camilla separated prizes for games at the carnival. She had 72 Choco Bars and 90 Peanut Blitzes. She put the most candy bars possible in each bag without mixing the two types. Each bag needed an equal amount of candy. How many candy bars did she put in each bag?

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Solution

To solve this problem, we need to find the greatest common divisor (GCD) of 72 (the number of Choco Bars) and 90 (the number of Peanut Blitzes). The GCD is the largest number that divides both numbers without leaving a remainder.

Here are the steps to find the GCD of 72 and 90:

  1. List the prime factors of each number:

    • Prime factors of 72: 2, 2, 2, 3, 3
    • Prime factors of 90: 2, 3, 3, 5

  2. Identify the common prime factors:

    • Common prime factors: 2, 3, 3

  3. Multiply the common prime factors together to find the GCD:

    • GCD = 2 * 3 * 3 = 18

So, Camilla put 18 candy bars in each bag.

This problem has been solved

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