What will be the value in EAX after the following lines execute?mov eax, 1002FFFFhneg ax

The given code is in Assembly language. Let's break it down:

1. mov eax, 1002FFFFh: This line moves the hexadecimal value 1002FFFF into the EAX register.

2. neg ax: This line negates the lower 16 bits of the EAX register.

The neg instruction computes the two's complement of the operand. The two's complement of a binary number is obtained by inverting the bits and adding 1 to the result.

The lower 16 bits of 1002FFFFh are 2FFFFh which is 0010 1111 1111 1111 in binary.

Inverting the bits gives 1101 0000 0000 0000 and adding 1 gives 1101 0000 0000 0001 which is D001h in hexadecimal.

So, after the neg ax instruction, the EAX register will contain 1002D001h.