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The teacher used 1.00 g of magnesium.Use the equation to calculate the maximum mass of magnesium oxide produced.Page 5Give your answer to three significant figures.Relative atomic masses (A r): O = 16; Mg = 24

Question

The teacher used 1.00 g of magnesium.Use the equation to calculate the maximum mass of magnesium oxide produced.Page 5Give your answer to three significant figures.Relative atomic masses (A r): O = 16; Mg = 24

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Solution

The equation for the reaction of magnesium with oxygen is:

2Mg + O2 → 2MgO

From the equation, we can see that 2 moles of Mg react with 1 mole of O2 to produce 2 moles of MgO.

First, we need to convert the mass of magnesium used to moles. The relative atomic mass (Ar) of Mg is given as 24, so:

Moles of Mg = mass / Ar = 1.00g / 24 = 0.0417 moles

According to the equation, 1 mole of Mg produces 1 mole of MgO. Therefore, 0.0417 moles of Mg will produce 0.0417 moles of MgO.

Next, we convert the moles of MgO to mass. The relative formula mass (Mr) of MgO is (24 + 16) = 40, so:

Mass of MgO = moles x Mr = 0.0417 x 40 = 1.67g

So, the maximum mass of magnesium oxide that can be produced from 1.00g of magnesium is 1.67g to three significant figures.

This problem has been solved

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