f X is a random variable with possible outcomes 3 and 8, with P( X = 3) = 0, then E(X) is
Question
f X is a random variable with possible outcomes 3 and 8, with P( X = 3) = 0, then E(X) is
Solution
The expected value (E(X)) of a random variable is calculated as the sum of all possible outcomes each multiplied by their respective probabilities.
In this case, X can take on the values 3 and 8.
Given that P(X = 3) = 0, this means that the random variable X will never take on the value 3.
The only other possible outcome for X is 8. Since these are the only two possible outcomes, and X can't be 3, the probability that X = 8 must be 1 (because the sum of the probabilities of all possible outcomes must equal 1).
So, we can calculate E(X) as follows:
E(X) = (3 * P(X = 3)) + (8 * P(X = 8)) = (3 * 0) + (8 * 1) = 0 + 8 = 8
Therefore, E(X) = 8.
Similar Questions
f the random variable X assumes the values 0 and 1 only and is such that P(X = 0) = 3P(X = 1), then the value of E(X) isans.
If the random variable X assumes the values 0 and 1 only and is such that P(X = 0) = 3P(X = 1), then the value of E(X) is ans. 1/4 2/3 none 1/3
E(X-E(X)) is
If the random variable X assumes the values 0 and 1 only and is such that P(X = 0) = 3P(X =
If X follows Binomial distribution with mean 3 and variance 2 , then P(X≥8) is equal to :1739183919392039
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.