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Age of the father is twice that of the elder son. Ten years hence the age of the father will be three times that of the younger son. If the difference of the ages of the two sons is 15 years, the age (in years) of the father is?Options70555060

Question

Age of the father is twice that of the elder son. Ten years hence the age of the father will be three times that of the younger son. If the difference of the ages of the two sons is 15 years, the age (in years) of the father is?Options70555060

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Solution

Let's denote the current age of the elder son as E, the current age of the younger son as Y, and the current age of the father as F.

From the problem, we know that:

  1. F = 2E (The father's age is twice that of the elder son)

  2. F + 10 = 3(Y + 10) (In ten years, the father's age will be three times that of the younger son)

  3. E - Y = 15 (The difference in age between the two sons is 15 years)

We can substitute F from the first equation into the second equation to get:

2E + 10 = 3Y + 30

Solving this equation for E gives us:

E = 3Y/2 + 10

Substituting Y = E - 15 from the third equation into this equation gives us:

E = 3(E - 15)/2 + 10

Solving this equation for E gives us:

E = 30

Substituting E = 30 into the first equation gives us:

F = 2 * 30 = 60

So, the father's current age is 60 years.

This problem has been solved

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