What will be the output of the following pseudocode for a = 2, b = 6?Integer funn(Integer a, Integer b If(a > 0) If(b > 0) Return a + b + funn(a + 1, 0) + funn(a + 2, 0) + funn(a + 3, 0) End If End If Return a + bEnd Function funn() Question 85AnswerA.17B.21C.37D.20
Question
What will be the output of the following pseudocode for a = 2, b = 6?Integer funn(Integer a, Integer b If(a > 0) If(b > 0) Return a + b + funn(a + 1, 0) + funn(a + 2, 0) + funn(a + 3, 0) End If End If Return a + bEnd Function funn() Question 85AnswerA.17B.21C.37D.20
Solution
The pseudocode provided is a recursive function. Let's break it down step by step:
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We start with a = 2 and b = 6. Since a > 0 and b > 0, we enter the first if condition and the return statement is a + b + funn(a + 1, 0) + funn(a + 2, 0) + funn(a + 3, 0).
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For funn(a + 1, 0), a = 3 and b = 0. Since a > 0 but b is not > 0, we skip the first if condition and go to the return statement which is a + b = 3 + 0 = 3.
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For funn(a + 2, 0), a = 4 and b = 0. Similarly, the return statement is a + b = 4 + 0 = 4.
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For funn(a + 3, 0), a = 5 and b = 0. The return statement is a + b = 5 + 0 = 5.
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Adding all these values together, we get 2 + 6 + 3 + 4 + 5 = 20.
So, the output of the pseudocode for a = 2, b = 6 is 20. Therefore, the correct answer is D.20.
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