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What will be the output of the following pseudocode for a = 2, b = 6?Integer funn(Integer a, Integer b  If(a > 0)    If(b > 0)      Return a + b + funn(a + 1, 0) + funn(a + 2, 0) + funn(a + 3, 0)    End If  End If  Return a + bEnd Function funn() Question 85AnswerA.17B.21C.37D.20

Question

What will be the output of the following pseudocode for a = 2, b = 6?Integer funn(Integer a, Integer b  If(a > 0)    If(b > 0)      Return a + b + funn(a + 1, 0) + funn(a + 2, 0) + funn(a + 3, 0)    End If  End If  Return a + bEnd Function funn() Question 85AnswerA.17B.21C.37D.20

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Solution

The pseudocode provided is a recursive function. Let's break it down step by step:

  1. We start with a = 2 and b = 6. Since a > 0 and b > 0, we enter the first if condition and the return statement is a + b + funn(a + 1, 0) + funn(a + 2, 0) + funn(a + 3, 0).

  2. For funn(a + 1, 0), a = 3 and b = 0. Since a > 0 but b is not > 0, we skip the first if condition and go to the return statement which is a + b = 3 + 0 = 3.

  3. For funn(a + 2, 0), a = 4 and b = 0. Similarly, the return statement is a + b = 4 + 0 = 4.

  4. For funn(a + 3, 0), a = 5 and b = 0. The return statement is a + b = 5 + 0 = 5.

  5. Adding all these values together, we get 2 + 6 + 3 + 4 + 5 = 20.

So, the output of the pseudocode for a = 2, b = 6 is 20. Therefore, the correct answer is D.20.

This problem has been solved

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