What is the mass of carbon-12 that contains the same number of atoms as 14 g of silicon-28?

Sure, let's solve this step by step:

1. First, we need to find the number of moles in 14g of Silicon-28. We use the formula: Number of moles = mass / molar mass Silicon has a molar mass of 28 g/mol, so the number of moles in 14g of Silicon is 14g / 28 g/mol = 0.5 mol.

2. The number of atoms in a sample can be found by multiplying the number of moles by Avogadro's number (6.022 x 10^23 atoms/mol). So, the number of atoms in 14g of Silicon is 0.5 mol x 6.022 x 10^23 atoms/mol = 3.011 x 10^23 atoms.

3. Now, we want to find the mass of Carbon-12 that contains this same number of atoms. We start by finding the number of moles of Carbon-12 that would contain this number of atoms. We divide the number of atoms by Avogadro's number: 3.011 x 10^23 atoms / 6.022 x 10^23 atoms/mol = 0.5 mol.

4. Finally, we find the mass of this number of moles of Carbon-12 by multiplying by its molar mass (12 g/mol): 0.5 mol x 12 g/mol = 6g.

So, the mass of Carbon-12 that contains the same number of atoms as 14g of Silicon-28 is 6g.