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Two numbers are less than a third number by 30% and 37% respectively.How much percent is the second number less than the first?10%70%4%3%

Question

Two numbers are less than a third number by 30% and 37% respectively.How much percent is the second number less than the first?10%70%4%3%

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Solution

Let's denote the third number as x.

  1. The first number is less than x by 30%, so it is 70% of x. We can write this as 0.7x.

  2. The second number is less than x by 37%, so it is 63% of x. We can write this as 0.63x.

  3. To find out how much percent the second number is less than the first, we need to express the difference between the first and second numbers as a percentage of the first number.

  4. The difference between the first and second numbers is 0.7x - 0.63x = 0.07x.

  5. To express this difference as a percentage of the first number, we divide it by the first number and multiply by 100: (0.07x / 0.7x) * 100 = 10%.

So, the second number is 10% less than the first number.

This problem has been solved

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