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The total mass of the skydiver with his parachute is 85.0 kilograms. If the magnitude of the gravitational forceis 834 newtons, and the magnitude of the force of air friction is 652 newtons, the acceleration of the skydiverat the time shown is

Question

The total mass of the skydiver with his parachute is 85.0 kilograms. If the magnitude of the gravitational forceis 834 newtons, and the magnitude of the force of air friction is 652 newtons, the acceleration of the skydiverat the time shown is

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Solution

To find the acceleration of the skydiver, we first need to find the net force acting on the skydiver.

The net force can be calculated by subtracting the force of air friction from the gravitational force.

Net Force = Gravitational Force - Force of Air Friction Net Force = 834 N - 652 N = 182 N

Next, we use Newton's second law of motion, which states that the acceleration of an object is equal to the net force acting on it divided by its mass.

Acceleration = Net Force / Mass Acceleration = 182 N / 85.0 kg = 2.14 m/s²

So, the acceleration of the skydiver at the time shown is 2.14 m/s².

This problem has been solved

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