Inverse laplace transform of ๐ฟโ11๐ 2+๐2L โ1 s 2 +a 2 1โ =a)1๐๐๐๐ ๐๐กa1โ cosatb)1๐๐ ๐๐๐๐กa1โ sinatc)1๐๐ ๐๐๐กa1โ sintd)1๐๐๐๐ ๐กa1โ cost
Question
Inverse laplace transform of ๐ฟโ11๐ 2+๐2L โ1 s 2 +a 2 1โ =a)1๐๐๐๐ ๐๐กa1โ cosatb)1๐๐ ๐๐๐๐กa1โ sinatc)1๐๐ ๐๐๐กa1โ sintd)1๐๐๐๐ ๐กa1โ cost
Solution
The inverse Laplace transform of 1/(s^2 + a^2) is b) 1/a sin(at). This is a standard result in Laplace transform tables. The function 1/(s^2 + a^2) corresponds to the sine function in the time domain, scaled by 1/a.
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