public class Main { public static void change(int input[]){ input = new int[5]; input[0] = 15; } public static void main(String args[]){ int arr[] = new int[5]; change(arr); System.out.println(arr[0]); }}
Question
public class Main { public static void change(int input[]){ input = new int[5]; input[0] = 15; } public static void main(String args[]){ int arr[] = new int[5]; change(arr); System.out.println(arr[0]); }}
Solution
The code you provided is written in Java. It defines a class named Main with two methods: change and main.
The change method takes an array of integers as an input, creates a new array of integers with a length of 5, and assigns the value 15 to the first element of this new array.
The main method creates an array of integers with a length of 5, calls the change method with this array as an argument, and then prints the first element of the array.
However, the output of this code will be 0, not 15. This is because Java is pass-by-value, meaning that when you pass the array to the change method, you are passing the reference (or address) of the array, not the actual array itself. When you create a new array in the change method, you are not modifying the original array but creating a new one. Therefore, the original array remains unchanged, and since you didn't assign any values to it, the first element is 0 (the default value for integers in Java).
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