The code you provided will result in a TypeError. This is because the function `display_person(*args)` is expecting positional arguments, but you are providing keyword arguments (`name="Emma", age="25"`).

If you want to use keyword arguments, you should define your function with `**kwargs` instead of `*args`. Here's how you can do it:

```python
def display_person(**kwargs):
for key, value in kwargs.items():
print(key, value)

display_person(name="Emma", age="25")
```

This will output:

```
name Emma
age 25
```

In this version of the function, `kwargs` is a dictionary that contains the names of the arguments as keys and their values as the dictionary values.

Question

The code you provided will result in a TypeError. This is because the function `display_person(*args)` is expecting positional arguments, but you are providing keyword arguments (`name="Emma", age="25"`).

If you want to use keyword arguments, you should define your function with `**kwargs` instead of `*args`. Here's how you can do it:

```python
def display_person(**kwargs):
    for key, value in kwargs.items():
        print(key, value)

display_person(name="Emma", age="25")
```

This will output:

```
name Emma
age 25
```

In this version of the function, `kwargs` is a dictionary that contains the names of the arguments as keys and their values as the dictionary values.

Knowee AI · Accepted Answer

The code you provided will result in a TypeError. This is because the function `display_person(*args)` is expecting positional arguments, but you are providing keyword arguments (`name="Emma", age="25"`).

If you want to use keyword arguments, you should define your function with `**kwargs` instead of `*args`. Here's how you can do it:

```python
def display_person(**kwargs):
    for key, value in kwargs.items():
        print(key, value)

display_person(name="Emma", age="25")
```

This will output:

```
name Emma
age 25
```

In this version of the function, `kwargs` is a dictionary that contains the names of the arguments as keys and their values as the dictionary values.

What is the output of the following display_person() function calldef display_person(*args): for i in args: print(i)display_person(name="Emma", age="25")TypeErrorEmma25nameage

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