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he tangent line at $$x=0 has been graphed, and its equation can be approximated by $$y=2.1x+3. Use the tangent to calculate the instantaneous rate of change at $$x=0.

Question

he tangent line at x=0 has been graphed, and its equation can be approximated by y=2.1x+3. Use the tangent to calculate the instantaneous rate of change at x=0.

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Solution

Para calcular la tasa de cambio instantánea en x=0x=0 usando la línea tangente, seguimos estos pasos:

  1. Identificar la ecuación de la línea tangente: La ecuación dada es y=2.1x+3y = 2.1x + 3.

  2. Entender la relación de la línea tangente con la derivada: La pendiente de la línea tangente en un punto específico es igual a la derivada de la función en ese punto. En este caso, la pendiente de la línea tangente es 2.1.

  3. Determinar la tasa de cambio instantánea: La tasa de cambio instantánea en x=0x=0 es igual a la pendiente de la línea tangente en ese punto.

Por lo tanto, la tasa de cambio instantánea en x=0x=0 es 2.12.1.

This problem has been solved

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The topic is the application of function derivatives. The first task: Find the equation of the tangent line to 𝑦=2𝑥2−𝑥+3 at 𝑥0=0.5 Give explanations and formulas and draw a graph if needed

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