answerIf 6 men and 8 boys can do a piece of work in 10 days and 26 men and 48 boys can do the same in 2 days, then the time taken by 15 men and 20 boys to do the same type of work will be?Options5 days6 days4 days7 days

The problem can be solved using the concept of man-days (a unit of work done by one person in one day).

Step 1: Let's assume the amount of work done by one man in one day is m and by one boy in one day is b.

Step 2: According to the first condition, 6 men and 8 boys can do the work in 10 days. So, we can write this as: 10(6m + 8b) = 1 (where 1 represents the total work)

Step 3: According to the second condition, 26 men and 48 boys can do the work in 2 days. So, we can write this as: 2(26m + 48b) = 1

Step 4: Now we have a system of two equations, and we can solve it to find the values of m and b.

Step 5: After finding the values of m and b, we can find the time taken by 15 men and 20 boys to do the same work. Let's denote this time as T. So, we have the equation: T(15m + 20b) = 1

Step 6: Solve this equation to find the value of T.

Without actual values, we can't determine the exact answer. But this is the step-by-step process to solve this problem.