s x2 + y3 odd?(1) x2y = 48(2) xy2 = 36

To determine if s x2 + y3 is odd, we need to analyze the given statements.

Statement 1: x2y = 48 Statement 2: xy2 = 36

Let's solve each statement step by step:

Statement 1: From x2y = 48, we can rearrange the equation to get y = 48 / x2. This equation does not provide any information about the parity of y, so it does not help us determine if s x2 + y3 is odd.

Statement 2: From xy2 = 36, we can rearrange the equation to get x = 36 / y2. Similar to statement 1, this equation does not provide any information about the parity of x.

Combining both statements: By combining the equations from both statements, we can substitute the value of x from statement 2 into statement 1 or vice versa. However, this does not help us determine the parity of s x2 + y3.

Therefore, neither statement alone nor the combination of both statements is sufficient to determine if s x2 + y3 is odd.