Which one of the following statements about normal forms is FALSE? (PERSISTENT)Options: Pick one correct answer from belowLossless, dependency -preserving decomposition into 3 NF is always possibleBCNF is stricter than 3 NFLoss less, dependency – preserving decomposition into BCNF is always possibleAny relation with two attributes is BCNF
Question
Which one of the following statements about normal forms is FALSE? (PERSISTENT)Options: Pick one correct answer from belowLossless, dependency -preserving decomposition into 3 NF is always possibleBCNF is stricter than 3 NFLoss less, dependency – preserving decomposition into BCNF is always possibleAny relation with two attributes is BCNF
Solution
The false statement is: "Loss less, dependency – preserving decomposition into BCNF is always possible". This is because it's not always possible to have a lossless, dependency-preserving decomposition into BCNF. There are cases where a relation can be decomposed into BCNF in a lossless manner, but not in a dependency-preserving way.
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Which one of the following statements about normal forms is FALSE?
Which normal form deals with the elimination of transitive dependencies?Question 10Answera.Boyce-Codd Normal Form (BCNF)b.Third Normal Form (3NF)c.First Normal Form (1NF)d.Second Normal Form (2NF)
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Which of the following statements about dependency preservation is true?Dependency preservation ensures that all relations are in 2nd Normal Form (2NF).It guarantees that no transitive dependencies exist in a relation.Dependency preservation is only relevant for relations with composite keys.It ensures that the decomposition of relations during normalization maintains the same functional dependencies.Next
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