A panel for a political forum is made up of 13 people from three parties, all seated in a row. The panel consists of 4 Socialists, 1 Republican, and 8 Green Party members. In how many distinct orders can they be seated if two people of the same party are considered identical (not distinct)?
Question
A panel for a political forum is made up of 13 people from three parties, all seated in a row. The panel consists of 4 Socialists, 1 Republican, and 8 Green Party members. In how many distinct orders can they be seated if two people of the same party are considered identical (not distinct)?
Solution
To solve this problem, we can use the formula for permutations of a multiset. This formula is n! / (n1! * n2! * ... * nk!), where n is the total number of items, and n1, n2, ..., nk are the numbers of each type of item.
In this case, n = 13 (the total number of people), n1 = 4 (the number of Socialists), n2 = 1 (the number of Republicans), and n3 = 8 (the number of Green Party members).
So, the number of distinct orders in which they can be seated is 13! / (4! * 1! * 8!) = 34650.
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