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Consider the following scenario: • A table is sorted on indexed column and has 10,000,000 rows. • Each row is 200 bytes. • Table and index blocks are 4 kilobytes. • Assume 1 kilobyte is approximately 1,000 bytes.Assuming the index is sparse, how many entries are in the index?

Question

Consider the following scenario: • A table is sorted on indexed column and has 10,000,000 rows. • Each row is 200 bytes. • Table and index blocks are 4 kilobytes. • Assume 1 kilobyte is approximately 1,000 bytes.Assuming the index is sparse, how many entries are in the index?

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Solution

To calculate the number of entries in the index, we first need to determine how many rows fit into a block.

  1. Calculate the size of a block in bytes: 4 kilobytes * 1000 bytes/kilobyte = 4000 bytes/block
  2. Calculate the number of rows per block: 4000 bytes/block / 200 bytes/row = 20 rows/block
  3. Since the index is sparse, there is one index entry for each block. So, the number of entries in the index is equal to the number of blocks.
  4. Calculate the number of blocks (and thus index entries): 10,000,000 rows / 20 rows/block = 500,000 entries

So, there are 500,000 entries in the index.

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