A rock, 1.2 kg, was thrown into the air. As it reaches its maximum height gravity begins to work on it. How much force is being put on the rock as it falls? Use the equation triangle you filled out for number 2122) What is the answer?1 point0.1 N11.8 N8.2 N
Question
A rock, 1.2 kg, was thrown into the air. As it reaches its maximum height gravity begins to work on it. How much force is being put on the rock as it falls? Use the equation triangle you filled out for number 2122) What is the answer?1 point0.1 N11.8 N8.2 N
Solution
The force acting on the rock as it falls is due to gravity. This force can be calculated using the formula:
F = m * g
where: F is the force, m is the mass of the rock, and g is the acceleration due to gravity.
Given that the mass of the rock (m) is 1.2 kg and the acceleration due to gravity (g) is approximately 9.8 m/s², we can substitute these values into the formula:
F = 1.2 kg * 9.8 m/s² = 11.76 N
Therefore, the force being put on the rock as it falls is approximately 11.8 N.
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