What volume is occupied by 0.34 moles of Helium gas?

To find the volume occupied by 0.34 moles of Helium gas, we can use the ideal gas law equation, which is PV = nRT.

Here, P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

Assuming that the gas is at standard temperature and pressure (STP), we can use the conditions of STP where the temperature T is 273.15 K and the pressure P is 1 atm.

The ideal gas constant R is 0.0821 L·atm/(K·mol) under these conditions.

Substituting these values into the ideal gas law equation, we get:

V = nRT/P

V = 0.34 moles * 0.0821 L·atm/(K·mol) * 273.15 K / 1 atm

After calculating the above expression, we find that the volume V is approximately 7.6 liters.

So, 0.34 moles of Helium gas occupies a volume of about 7.6 liters