The PHP code you provided will output "1". Here's the step by step explanation:

1. `$foo = 10;` This line is setting the variable `$foo` to the integer `10`.

2. `$bar = (boolean)$foo;` This line is casting the integer `10` to a boolean. In PHP, any integer that is not `0` is considered `true` when cast to a boolean.

3. `echo $bar;` This line is outputting the value of `$bar`. Since `$bar` is a boolean `true`, and `echo` outputs booleans as `1` for `true` and `0` for `false`, this will output `1`.

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The PHP code you provided will output "1". Here's the step by step explanation:

1. `$foo = 10;` This line is setting the variable `$foo` to the integer `10`.

2. `$bar = (boolean)$foo;` This line is casting the integer `10` to a boolean. In PHP, any integer that is not `0` is considered `true` when cast to a boolean.

3. `echo $bar;` This line is outputting the value of `$bar`. Since `$bar` is a boolean `true`, and `echo` outputs booleans as `1` for `true` and `0` for `false`, this will output `1`.

Knowee AI · Accepted Answer

The PHP code you provided will output "1". Here's the step by step explanation:

1. `$foo = 10;` This line is setting the variable `$foo` to the integer `10`.

2. `$bar = (boolean)$foo;` This line is casting the integer `10` to a boolean. In PHP, any integer that is not `0` is considered `true` when cast to a boolean.

3. `echo $bar;` This line is outputting the value of `$bar`. Since `$bar` is a boolean `true`, and `echo` outputs booleans as `1` for `true` and `0` for `false`, this will output `1`.

What will the following PHP code output?$foo = 10;$bar = (boolean)$foo;echo $bar;PHP Parse errorPHP Parse error: syntax error01

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