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For the population of scores shown in the frequency distribution table, the mean is ____.​​X         f5          24          13          32          21          2​Group of answer choices​29/5 = 5.80​29/10 = 2.90​15/10 = 1.50​15/5 = 3

Question

For the population of scores shown in the frequency distribution table, the mean is ____.​​X         f5          24          13          32          21          2​Group of answer choices​29/5 = 5.80​29/10 = 2.90​15/10 = 1.50​15/5 = 3

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Solution

Para encontrar la media de la población de puntuaciones mostrada en la tabla de distribución de frecuencias, seguimos estos pasos:

  1. Multiplicamos cada puntuación (X) por su frecuencia (f) para obtener el producto de cada par.
  2. Sumamos todos los productos obtenidos en el paso anterior.
  3. Sumamos todas las frecuencias.
  4. Dividimos la suma de los productos por la suma de las frecuencias.

Vamos a realizar estos pasos con los datos proporcionados:

  1. Productos de cada par:
    • 5 * 2 = 10
    • 4 * 1 = 4

This problem has been solved

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1/3

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