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Factor.x, squared, minus, 9, x, plus, 18x 2 −9x+18

Question

Factor.x, squared, minus, 9, x, plus, 18x 2 −9x+18

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Solution

The expression you provided seems to be a bit unclear, but I'm assuming you meant "Factor x^2 - 9x + 18". Here are the steps to factor this quadratic equation:

  1. Identify the coefficients of the quadratic equation. In this case, a = 1 (coefficient of x^2), b = -9 (coefficient of x), and c = 18 (constant term).

  2. Find two numbers that multiply to give ac (a times c), and add to give b. In this case, ac = 118 = 18 and b = -9. The numbers that fit these conditions are -6 and -3 because -6-3 = 18 and -6 + -3 = -9.

  3. Rewrite the middle term of the quadratic equation (the term involving x) as the sum of the terms with the two numbers found in step 2. This gives x^2 - 6x - 3x + 18.

  4. Factor by grouping. The first two terms can be grouped together, and the last two terms can be grouped together. This gives (x^2 - 6x) - (3x - 18).

  5. Factor out a common factor from each group. This gives x(x - 6) - 3(x - 6).

  6. Notice that (x - 6) is a common factor of both terms. Factor out (x - 6), which gives (x - 6)(x - 3).

So, the factored form of the equation x^2 - 9x + 18 is (x - 6)(x - 3).

This problem has been solved

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