A person bought some mangoes at the rate of 7 per rupee. He bought the same number of mangoes at the rate of 6 per rupee. He mixes both types and sells at 14 for rupees 6. In the business he earns a profit of Rs. 46. How many mangoes he bought in all.
Question
A person bought some mangoes at the rate of 7 per rupee. He bought the same number of mangoes at the rate of 6 per rupee. He mixes both types and sells at 14 for rupees 6. In the business he earns a profit of Rs. 46. How many mangoes he bought in all.
Solution
Let's solve this step by step:
Step 1: Let's assume the number of mangoes bought at each rate is x. So, total mangoes bought = 2x.
Step 2: The cost of mangoes bought at 7 per rupee is x/7 and at 6 per rupee is x/6. So, total cost = x/7 + x/6 = 13x/42.
Step 3: The selling price of mangoes is 14 for 6 rupees. So, for 2x mangoes, the selling price = (2x/14) * 6 = 6x/7.
Step 4: We know that profit = selling price - cost price. So, 46 = 6x/7 - 13x/42.
Step 5: Solving the above equation, we get x = 294.
So, the person bought 294 mangoes at each rate, making the total number of mangoes bought 2*294 = 588.
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