Identify the substances that is oxidized and the substances that is reduced in thefollowing reactions:CuO(s) + H2(g) Cu(s) + H2O(l)(a) H2, CuO (b) H2, H2O(c) H2, Cu (d) Cu, H2
Question
Identify the substances that is oxidized and the substances that is reduced in thefollowing reactions:CuO(s) + H2(g) Cu(s) + H2O(l)(a) H2, CuO (b) H2, H2O(c) H2, Cu (d) Cu, H2
Solution
In the given reaction, CuO(s) + H2(g) --> Cu(s) + H2O(l), we can identify the substances that are oxidized and reduced by looking at the changes in oxidation states.
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CuO(s) --> Cu(s): In this case, Cu is reduced from +2 oxidation state in CuO to 0 oxidation state in Cu. So, CuO is the substance that is reduced.
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H2(g) --> H2O(l): Here, H is oxidized from 0 oxidation state in H2 to +1 oxidation state in H2O. So, H2 is the substance that is oxidized.
Therefore, the correct answer is (a) H2, CuO. H2 is oxidized and CuO is reduced.
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