If a body has reflectivity of 0.6 and the power incident on it is 50W, which of the following can be the values of transmitted and absorbed energy? Transmitted = 5W, Absorbed = 10W Transmitted = 15W, Absorbed = 15W Transmitted = 5W, Absorbed = 15W Transmitted = 10W, Absorbed = 5W
Question
If a body has reflectivity of 0.6 and the power incident on it is 50W, which of the following can be the values of transmitted and absorbed energy? Transmitted = 5W, Absorbed = 10W Transmitted = 15W, Absorbed = 15W Transmitted = 5W, Absorbed = 15W Transmitted = 10W, Absorbed = 5W
Solution
The reflectivity of a body is the fraction of incident light that it reflects. In this case, the body has a reflectivity of 0.6, which means it reflects 60% of the incident light. The power incident on the body is 50W, so the power reflected by the body is 0.6 * 50W = 30W.
The remaining power, which is either transmitted or absorbed by the body, is 50W - 30W = 20W.
Now, let's check each of the given options:
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Transmitted = 5W, Absorbed = 10W: The total of transmitted and absorbed power is 5W + 10W = 15W, which is less than 20W. So, this option is not possible.
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Transmitted = 15W, Absorbed = 15W: The total of transmitted and absorbed power is 15W + 15W = 30W, which is more than 20W. So, this option is not possible.
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Transmitted = 5W, Absorbed = 15W: The total of transmitted and absorbed power is 5W + 15W = 20W, which is equal to the remaining power. So, this option is possible.
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Transmitted = 10W, Absorbed = 5W: The total of transmitted and absorbed power is 10W + 5W = 15W, which is less than 20W. So, this option is not possible.
Therefore, the only possible values for the transmitted and absorbed energy are 5W and 15W, respectively.
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