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If a body has reflectivity of 0.6 and the power incident on it is 50W, which of the following can be the values of transmitted and absorbed energy? Transmitted = 5W, Absorbed = 10W Transmitted = 15W, Absorbed = 15W Transmitted = 5W, Absorbed = 15W Transmitted = 10W, Absorbed = 5W

Question

If a body has reflectivity of 0.6 and the power incident on it is 50W, which of the following can be the values of transmitted and absorbed energy? Transmitted = 5W, Absorbed = 10W Transmitted = 15W, Absorbed = 15W Transmitted = 5W, Absorbed = 15W Transmitted = 10W, Absorbed = 5W

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Solution

The reflectivity of a body is the fraction of incident light that it reflects. In this case, the body has a reflectivity of 0.6, which means it reflects 60% of the incident light. The power incident on the body is 50W, so the power reflected by the body is 0.6 * 50W = 30W.

The remaining power, which is either transmitted or absorbed by the body, is 50W - 30W = 20W.

Now, let's check each of the given options:

  1. Transmitted = 5W, Absorbed = 10W: The total of transmitted and absorbed power is 5W + 10W = 15W, which is less than 20W. So, this option is not possible.

  2. Transmitted = 15W, Absorbed = 15W: The total of transmitted and absorbed power is 15W + 15W = 30W, which is more than 20W. So, this option is not possible.

  3. Transmitted = 5W, Absorbed = 15W: The total of transmitted and absorbed power is 5W + 15W = 20W, which is equal to the remaining power. So, this option is possible.

  4. Transmitted = 10W, Absorbed = 5W: The total of transmitted and absorbed power is 10W + 5W = 15W, which is less than 20W. So, this option is not possible.

Therefore, the only possible values for the transmitted and absorbed energy are 5W and 15W, respectively.

This problem has been solved

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