Sure, let's solve this step by step:

1. Let's denote the cost of a soccer ball as S and the cost of a baseball cap as C.

2. From the problem, we know that Edmund bought 3 soccer balls and 6 baseball caps for $192. So, we can write this as an equation: 3S + 6C = $192.

3. We also know that 1 soccer ball costs the same as 6 baseball caps. So, we can write this as another equation: S = 6C.

4. Now we can substitute the second equation into the first one to solve for C. Replacing S in the first equation with 6C gives us: 3(6C) + 6C = $192. Simplifying this gives us 18C + 6C = $192, which further simplifies to 24C = $192.

5. Solving for C, we find that C = $192 / 24 = $8. So, each baseball cap costs $8.

6. Substituting C = $8 into the second equation S = 6C gives us S = 6 * $8 = $48. So, each soccer ball costs $48.

Therefore, the cost of 1 soccer ball and 1 baseball cap is $48 + $8 = $56.

Question

Sure, let's solve this step by step:

1. Let's denote the cost of a soccer ball as S and the cost of a baseball cap as C.

2. From the problem, we know that Edmund bought 3 soccer balls and 6 baseball caps for $192. So, we can write this as an equation: 3S + 6C = $192.

3. We also know that 1 soccer ball costs the same as 6 baseball caps. So, we can write this as another equation: S = 6C.

4. Now we can substitute the second equation into the first one to solve for C. Replacing S in the first equation with 6C gives us: 3(6C) + 6C = $192. Simplifying this gives us 18C + 6C = $192, which further simplifies to 24C = $192.

5. Solving for C, we find that C = $192 / 24 = $8. So, each baseball cap costs $8.

6. Substituting C = $8 into the second equation S = 6C gives us S = 6 * $8 = $48. So, each soccer ball costs $48.

Therefore, the cost of 1 soccer ball and 1 baseball cap is $48 + $8 = $56.

Knowee AI · Accepted Answer

Sure, let's solve this step by step:

1. Let's denote the cost of a soccer ball as S and the cost of a baseball cap as C.

2. From the problem, we know that Edmund bought 3 soccer balls and 6 baseball caps for $192. So, we can write this as an equation: 3S + 6C = $192.

3. We also know that 1 soccer ball costs the same as 6 baseball caps. So, we can write this as another equation: S = 6C.

4. Now we can substitute the second equation into the first one to solve for C. Replacing S in the first equation with 6C gives us: 3(6C) + 6C = $192. Simplifying this gives us 18C + 6C = $192, which further simplifies to 24C = $192.

5. Solving for C, we find that C = $192 / 24 = $8. So, each baseball cap costs $8.

6. Substituting C = $8 into the second equation S = 6C gives us S = 6 * $8 = $48. So, each soccer ball costs $48.

Therefore, the cost of 1 soccer ball and 1 baseball cap is $48 + $8 = $56.

Edmund bought 3 soccer balls and 6 baseball caps for $192. If 1 soccer ball costs the same as 6 baseball caps, what is the cost of 1 soccer ball and 1 baseball cap?The cost of 1 soccer ball and 1 baseball cap is $.

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