What is the output of the code given below?#include <stdio.h> void main() { int i; for (i = 0; i < 10; i++); printf("%d ", i);}Options100Compilation Error0 1 2 3 4 5 6 7 8 9

The output of the given code will be 10.

Here's the step by step explanation:

1. The code starts with the inclusion of the stdio.h header file which is used for input/output operations in C.

2. The main function is declared with return type void, which means it doesn't return any value.

3. An integer variable 'i' is declared.

4. A for loop is initiated where 'i' is initialized to 0. The condition for the loop to run is 'i' less than 10 and 'i' is incremented by 1 at each iteration.

5. The semicolon (;) immediately after the for loop means that the loop has no body, so it will simply iterate from 0 to 9 without performing any operation.

6. After the loop has finished running, the printf function is called to print the value of 'i'. Since the loop increments 'i' until it is no longer less than 10, 'i' will be 10 when the loop finishes.

7. Therefore, the output of the program will be 10.