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Select the correct answerWhat will be the output of the following Python code?import reprint(re.split(r'(a\d)=', 'a1=4.5, a2=6, a3=9.865'))Options[”, ‘a1’, ‘4.5, ‘, ‘a2’, ‘6, ‘, ‘a3’, ‘9.865’][‘4.5, ‘, ‘6, ‘, ‘9.865’][‘a1’, ‘4.5, ‘, ‘a2’, ‘6, ‘, ‘a3’, ‘9.865’]Error

Question

Select the correct answerWhat will be the output of the following Python code?import reprint(re.split(r'(a\d)=', 'a1=4.5, a2=6, a3=9.865'))Options[”, ‘a1’, ‘4.5, ‘, ‘a2’, ‘6, ‘, ‘a3’, ‘9.865’][‘4.5, ‘, ‘6, ‘, ‘9.865’][‘a1’, ‘4.5, ‘, ‘a2’, ‘6, ‘, ‘a3’, ‘9.865’]Error

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Solution

The correct answer is [”, ‘a1’, ‘4.5, ‘, ‘a2’, ‘6, ‘, ‘a3’, ‘9.865’].

Here's the step by step explanation:

  1. The Python code is importing the 're' module, which provides support for regular expressions in Python.

  2. The 're.split' function is used to split the string where there is a match with the regular expression. In this case, the regular expression is 'a\d=', which matches any string that starts with 'a', followed by a digit (\d), and then an equals sign (=).

  3. The string 'a1=4.5, a2=6, a3=9.865' is split at each match with the regular expression.

  4. The resulting list is [”, ‘a1’, ‘4.5, ‘, ‘a2’, ‘6, ‘, ‘a3’, ‘9.865’]. The empty string at the beginning of the list is because there is nothing before the first match with the regular expression in the original string.

This problem has been solved

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