In Arizona, photovoltaic (PV) panels can generate an average annual power of 1 MW/acre. If there are 328 sunny days per year in Arizona, but only 148 sunny days per year in Pennsylvania, how much average power (in MW/acre) could the same PV panels generate in Pennsylvania? Please include two decimal places in your answer. Note: assume that a cloudy day delivers 0 watts/acre of solar power. This is not true, but it simplifies the problem for us.
Question
In Arizona, photovoltaic (PV) panels can generate an average annual power of 1 MW/acre. If there are 328 sunny days per year in Arizona, but only 148 sunny days per year in Pennsylvania, how much average power (in MW/acre) could the same PV panels generate in Pennsylvania? Please include two decimal places in your answer. Note: assume that a cloudy day delivers 0 watts/acre of solar power. This is not true, but it simplifies the problem for us.
Solution
To solve this problem, we need to find the ratio of sunny days in Pennsylvania to sunny days in Arizona and then multiply this ratio by the power generated in Arizona.
Step 1: Find the ratio of sunny days in Pennsylvania to sunny days in Arizona.
The number of sunny days in Pennsylvania is 148 and in Arizona is 328. So, the ratio is 148/328 = 0.45122.
Step 2: Multiply this ratio by the power generated in Arizona.
The power generated in Arizona is 1 MW/acre. So, the power generated in Pennsylvania would be 0.45122 * 1 MW/acre = 0.45122 MW/acre.
Therefore, the same PV panels could generate an average power of 0.45 MW/acre in Pennsylvania (rounded to two decimal places).
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