A 60 kg body moving with a speed of 5.0 m/s collides with a body twice its weight and moving at half its speed along the same direction. After the collision, the 60 kg body moves in the opposite direction with a speed of 2 m/s. Find the final velocity of the heavier body*1 point6 m/s60 m/s63 m/s68 m/s

To solve this problem, we need to use the principle of conservation of momentum. The total momentum before the collision is equal to the total momentum after the collision.

The initial momentum of the 60 kg body is its mass times its velocity, which is 60 kg * 5 m/s = 300 kg*m/s.

The initial momentum of the 120 kg body (which is twice the weight of the 60 kg body) is its mass times its velocity, which is 120 kg * 2.5 m/s = 300 kg*m/s.

So, the total initial momentum is 300 kgm/s + 300 kgm/s = 600 kg*m/s.

After the collision, the 60 kg body moves in the opposite direction with a speed of 2 m/s. So, its momentum is 60 kg * -2 m/s = -120 kg*m/s (the negative sign indicates that the direction has reversed).

Let's denote the final velocity of the heavier body as V. Its momentum after the collision is its mass times its velocity, which is 120 kg * V.

According to the principle of conservation of momentum, the total initial momentum (600 kg*m/s) is equal to the total final momentum. So, we have:

600 kgm/s = -120 kgm/s + 120 kg * V

Solving this equation for V gives:

V = (600 kgm/s + 120 kgm/s) / 120 kg = 6 m/s.

So, the final velocity of the heavier body is 6 m/s.

To solve this problem, we need to use the principle of conservation of momentum. The total momentum before the collision is equal to the total momentum after the collision.

Before the collision: The momentum of the 60 kg body is its mass times its velocity, which is 60 kg * 5 m/s = 300 kgm/s. The momentum of the 120 kg body is its mass times its velocity, which is 120 kg * 2.5 m/s = 300 kgm/s. So, the total momentum before the collision is 300 kgm/s + 300 kgm/s = 600 kg*m/s.

After the collision: The momentum of the 60 kg body is its mass times its velocity, which is 60 kg * -2 m/s = -120 kg*m/s (the negative sign indicates that it is moving in the opposite direction). Let's denote the final velocity of the 120 kg body as V. Its momentum after the collision is its mass times its velocity, which is 120 kg * V.

According to the principle of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision. Therefore, we have:

600 kgm/s = -120 kgm/s + 120 kg * V Solving this equation for V gives us V = (600 kgm/s + 120 kgm/s) / 120 kg = 6 m/s.

So, the final velocity of the heavier body is 6 m/s.