To find the limit of the function as x approaches negative infinity, we can divide every term by x^2, the highest power of x in the denominator.

The function then becomes:

lim(x→−∞) [(-3 + 12/x - 7/x^2) / (11 + 6/x + 15/x^2)]

As x approaches negative infinity, the terms 12/x, 7/x^2, 6/x, and 15/x^2 all approach 0.

So, the function simplifies to:

lim(x→−∞) (-3/11)

Therefore, the limit of the function as x approaches negative infinity is -3/11.

Question

To find the limit of the function as x approaches negative infinity, we can divide every term by x^2, the highest power of x in the denominator.

The function then becomes:

lim(x→−∞) [(-3 + 12/x - 7/x^2) / (11 + 6/x + 15/x^2)]

As x approaches negative infinity, the terms 12/x, 7/x^2, 6/x, and 15/x^2 all approach 0.

So, the function simplifies to:

lim(x→−∞) (-3/11)

Therefore, the limit of the function as x approaches negative infinity is -3/11.

Knowee AI · Accepted Answer

To find the limit of the function as x approaches negative infinity, we can divide every term by x^2, the highest power of x in the denominator.

The function then becomes:

lim(x→−∞) [(-3 + 12/x - 7/x^2) / (11 + 6/x + 15/x^2)]

As x approaches negative infinity, the terms 12/x, 7/x^2, 6/x, and 15/x^2 all approach 0.

So, the function simplifies to:

lim(x→−∞) (-3/11)

Therefore, the limit of the function as x approaches negative infinity is -3/11.

Find the limit.limx→−∞(−3x2+12x−711x2+6x+15)lim𝑥→−∞⁡(−3𝑥2+12𝑥−711𝑥2+6𝑥+15)