for a transistor, parameters are ß=180 and va= 150v and it is biased icq = 2ma. if collector of the transistor is connected to the base terminal, then small signal resistance re=vce/ic of this two terminal device is 12.87o12.88 k o2.33 k o12.53 o

To find the small signal resistance (re) of the transistor, we can use the formula re = Vce / Ic.

Given that ß (beta) is 180, Va is 150V, and Icq is 2mA, we need to calculate Vce first.

Vce can be calculated using the formula Vce = Va - Icq * (Rc + Re), where Rc is the collector resistance and Re is the emitter resistance.

Since the collector is connected to the base terminal, we can assume that Rc is very large, so we can neglect it in our calculations.

Now, let's calculate Vce: Vce = Va - Icq * Re

Given that Va is 150V and Icq is 2mA, we need to find Re.

Using the formula ß = Ic / Ib, we can calculate Ib: Ib = Ic / ß

Given that Ic is 2mA and ß is 180, we can calculate Ib: Ib = 2mA / 180

Now, let's calculate Re: Re = Vt / Ib

Where Vt is the thermal voltage, which is approximately 26mV at room temperature.

Using the calculated value of Ib, we can find Re: Re = 26mV / Ib

Finally, we can substitute the values of Va, Icq, and Re into the formula for Vce to find the small signal resistance (re): re = Vce / Ic

Substituting the calculated values, we can find the answer.