Given that one of the zeroes of the cubic polynomial ax3 + bx2 + cx + d is one, the product of the other two zeroes isSelect an answerA–c/a B–d/a C0Dc/a
Question
Given that one of the zeroes of the cubic polynomial ax3 + bx2 + cx + d is one, the product of the other two zeroes isSelect an answerA–c/a B–d/a C0Dc/a
Solution
The answer is B–d/a.
Here's the step-by-step solution:
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The sum of the zeroes of a cubic polynomial ax³ + bx² + cx + d = 0 is given by -b/a. If one of the zeroes is 1, then the sum of the other two zeroes is -b/a - 1.
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The product of the zeroes of a cubic polynomial is given by -d/a. If one of the zeroes is 1, then the product of the other two zeroes is -d/a divided by 1, which is -d/a.
So, the product of the other two zeroes is -d/a.
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