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Write left bracket, 7, plus, 3, i, right bracket, squared(7+3i) 2 in simplest a, plus, b, ia+bi form.

Question

Write left bracket, 7, plus, 3, i, right bracket, squared(7+3i) 2 in simplest a, plus, b, ia+bi form.

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Solution

To square a complex number, we use the formula (a + bi)^2 = a^2 + 2abi - b^2.

Here, a = 7 and b = 3.

Step 1: Square a: a^2 = 7^2 = 49

Step 2: Multiply a and b by 2: 2ab = 2 * 7 * 3 = 42

Step 3: Square b: b^2 = 3^2 = 9

Step 4: Substitute a^2, 2ab, and b^2 into the formula: (a + bi)^2 = a^2 + 2abi - b^2 (7 + 3i)^2 = 49 + 42i - 9

Step 5: Simplify the equation: (7 + 3i)^2 = 40 + 42i

So, (7 + 3i)^2 in simplest a + bi form is 40 + 42i.

This problem has been solved

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