Sure, let's solve this step by step:

1. A three-digit number is in the form of 100a + 10b + c, where a, b, and c are the digits of the number.

2. When the digits are reversed, the number becomes 100c + 10b + a.

3. According to the problem, the reversed number is 99 more than the original number. So, we can set up the equation: 100c + 10b + a = 100a + 10b + c + 99.

4. Simplifying this equation, we get 99c - 99a = 99, or a - c = 1.

5. Since a and c are digits, the only possible values for them are a = 1, c = 0; a = 2, c

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Sure, let's solve this step by step:

1. A three-digit number is in the form of 100a + 10b + c, where a, b, and c are the digits of the number.

2. When the digits are reversed, the number becomes 100c + 10b + a.

3. According to the problem, the reversed number is 99 more than the original number. So, we can set up the equation: 100c + 10b + a = 100a + 10b + c + 99.

4. Simplifying this equation, we get 99c - 99a = 99, or a - c = 1.

5. Since a and c are digits, the only possible values for them are a = 1, c = 0; a = 2, c

Knowee AI · Accepted Answer

Sure, let's solve this step by step:

1. A three-digit number is in the form of 100a + 10b + c, where a, b, and c are the digits of the number.

2. When the digits are reversed, the number becomes 100c + 10b + a.

3. According to the problem, the reversed number is 99 more than the original number. So, we can set up the equation: 100c + 10b + a = 100a + 10b + c + 99.

4. Simplifying this equation, we get 99c - 99a = 99, or a - c = 1.

5. Since a and c are digits, the only possible values for them are a = 1, c = 0; a = 2, c

How many three-digit numbers are increased by 99 when their digits are reversed?

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