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Rahul wants to play a poker game. The entry charge for the game is ₹2,000, which is non-refundable, and the probability that Rahul will win a poker game is 3%. The prize money is ₹50,000. If Rahul wins, he gets the prize money. If he loses, he gets nothing. What is his expected earning/loss per game? Note:1. Round off your final answer to two decimal places. If your answer is 1.333333, write 1.33 in the box.2. If the expectation is a loss, make sure you write a negative number. For instance, −2.5 is a valid answer.

Question

Rahul wants to play a poker game. The entry charge for the game is ₹2,000, which is non-refundable, and the probability that Rahul will win a poker game is 3%. The prize money is ₹50,000. If Rahul wins, he gets the prize money. If he loses, he gets nothing. What is his expected earning/loss per game? Note:1. Round off your final answer to two decimal places. If your answer is 1.333333, write 1.33 in the box.2. If the expectation is a loss, make sure you write a negative number. For instance, −2.5 is a valid answer.

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Solution

To calculate the expected earnings/loss per game, we need to multiply the outcome of each event by the probability of each event and then sum these values.

There are two possible outcomes in this scenario: Rahul wins the game or Rahul loses the game.

  1. If Rahul wins the game, his net gain is the prize money minus the entry fee, which is ₹50,000 - ₹2,000 = ₹48,000. The probability of this happening is 3%, or 0.03 in decimal form.

  2. If Rahul loses the game, his net loss is the entry fee, which is ₹2,000. The probability of this happening is 97%, or 0.97 in decimal form.

So, the expected earnings/loss per game is:

(₹48,000 * 0.03) + (₹-2,000 * 0.97) = ₹1,440 - ₹1,940 = ₹-500

So, Rahul's expected loss per game is ₹-500.

This problem has been solved

Similar Questions

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